You can put this solution on YOUR website! log3 + 2 = log x
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log(x) - log(3) = 2
log(x/3) = 2
x/3 = 10^2
x/3 = 100
x = 300
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Cheers,
Stan H.
You can put this solution on YOUR website! You will need to apply "log rules".
Review them at:
http://www.purplemath.com/modules/logrules.htm
.
log3 + 2 = log x
log3 - log x = -2
log(3/x) = -2
3/x = 10^(-2)
3/x = 0.01
3 = 0.01x
3/0.01 = x
300 = x