Question 186591: please help me solve these problems thank you
Find the vertex and intercepts of the parabola
y=-3x2square+6x
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! Standard vertex form:
y= a(x-h)^2+k
where
(h,k) is the vertex
.
y=-3x^2+6x
y=-3(x^2-2x)
At this point, you "complete the square"
y=-3(x^2-2x+1) + 3
y=-3(x^2-1)^2 + 3
.
By inspection...
Therefore, the vertex is at (1,3)
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