SOLUTION: Regarding Question 186543, I got your answer and I appreciate it very much, but if its not too much trouble could you please show me how you arrived at the number 12 for the AC, I

Algebra ->  Triangles -> SOLUTION: Regarding Question 186543, I got your answer and I appreciate it very much, but if its not too much trouble could you please show me how you arrived at the number 12 for the AC, I       Log On


   

Question 186566: Regarding Question 186543, I got your answer and I appreciate it very much, but if its not too much trouble could you please show me how you arrived at the number 12 for the AC, I hope I can follow it from there.
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

I've seen your problem--->the tutor answered it following the Ratio 3:4:5 , if "AC" being the shortest. Multiply each by 4 in the ratio---->3*4=12="AC": 4*4=16="BC" : 5*4=20="AB"
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You got it?
Now, just a comment on this: If it's in the Ratio of 3:4:5, it forms a RIGHT TRIANGLE:
--->Proof: 5%5E2=3%5E2%2B4%5E2-->25=9%2B16-->25=25
Finding for "AC":
20%5E2=AC%5E2%2B16%5E2
AC%5E2=400-256=144--->AC=sqrt%28144%29=highlight%2812yds%29
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Then, P=AB%2BBC%2BAC=20%2B16%2B12=highlight%2848+yds%29
Also, A=%281%2F2%29%28BC%29%28AC%29=%281%2F2%29%2816%29%2812%29=highlight%2896sqyds%29
The computations are right, as computed previously.
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Sorry, this is not to overemphasized the previous answer. We're just trying to make it clear for the student.
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Thank you,
Jojo