SOLUTION: Solve the System. 2x+3y+2z=1 2x-3y+2z=-1 4x+3y-2z=4 x= y= z=

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Question 186542: Solve the System.
2x+3y+2z=1
2x-3y+2z=-1
4x+3y-2z=4
x=
y=
z=
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
2x + 3y + 2z = 1
2x - 3y + 2z =-1
4x + 3y - 2z = 4
:
Use elimination with subtraction on 1st two equations
2x + 3y + 2z = 1
2x - 3y + 2z =-1
------------------
0x + 6y + 0z = 2
6y = 2
y = 2%2F6 = 1%2F3
:
Add the last two equations, eliminate y & z, find x
2x - 3y + 2z =-1
4x + 3y - 2z = 4
------------------
6x + 0y + 0z = 3
6x = 3
x = 3%2F6 = 1%2F2
:
Using the 1st equation, substitute for x & y, to find z
2(1%2F2) + 3(1%2F3) + 2z = 1
1 + 1 + 2z = 1
2z = 1 - 2
z = -1%2F2
;
;
You can check the solutions in the 2nd and 3rd equation