SOLUTION: Peanuts worth $2.90 per pound were mixed with cashews worth $4.60 per pound to make 51 pounds of a mixture worth $3.50 per pound. How many pounds of each were used? Put x= pounds

Click here to see ALL problems on Mixture Word Problems

Question 186507: Peanuts worth $2.90 per pound were mixed with cashews worth $4.60 per pound to make 51 pounds of a mixture worth $3.50 per pound. How many pounds of each were used?
Put x= pounds of peanuts and y= pound of cashews and make the equations as follows:
2.9*x + 4.6*y = 3.5*(x+y)
x + y = 51
solve the 2 equations as follos:
2.9x + 4.6y = 3.5*(x+y)= 3.5*51= 178.5
make x+y = 51 becomes -2.9x -2.9y =-2.9*51= -147.9
===> 4.6y-2.9y = 178.5- 147.9
1.7y = 30.6
y = 30.6/1.7
y = 18
then x= 51 - 18 = 33
conclusion: peanuts have 18pounds and cashew have 33 pounds to be used.
Found 2 solutions by stanbon, dukesmart:
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Peanuts worth $2.90 per pound were mixed with cashews worth $4.60 per pound to make 51 pounds of a mixture worth $3.50 per pound. How many pounds of each were used?
======
Equation:
value + value = value
290x + 460(51-x) = 350*51
---
290x + 460*51 - 460x = 350*51
---
-170x = -110*51
x = 33 lbs (amt. of $2.90 peanuts)
51- 33 = 18 lbs (amt. of $4.60 cashews)
==========================
Cheers,
Stan H.

Answer by dukesmart(20) (Show Source):
You can put this solution on YOUR website!
Peanuts worth $2.90 per pound were mixed with cashews worth $4.60 per pound to make 51 pounds of a mixture worth $3.50 per pound. How many pounds of each were used?
Put x= pounds of peanuts and y= pound of cashews and make the equations as follows:
2.9*x + 4.6*y = 3.5*(x+y)
x + y = 51
solve the 2 equations as follos:
2.9x + 4.6y = 3.5*(x+y)= 3.5*51= 178.5
make x+y = 51 becomes -2.9x -2.9y =-2.9*51= -147.9
===> 4.6y-2.9y = 178.5- 147.9
1.7y = 30.6
y = 30.6/1.7
y = 18
then x= 51 - 18 = 33
conclusion: peanuts have 18pounds and cashew have 33 pounds to be used.