SOLUTION: Could someone help me with this problem: (2/3)^-2(4/5)^-1 I am suppose to write it in simplest form without negative exponents. I am usually good in algebra but since I

Algebra ->  Exponents -> SOLUTION: Could someone help me with this problem: (2/3)^-2(4/5)^-1 I am suppose to write it in simplest form without negative exponents. I am usually good in algebra but since I       Log On


   



Question 186458: Could someone help me with this problem:
(2/3)^-2(4/5)^-1
I am suppose to write it in simplest form without negative exponents.
I am usually good in algebra but since I got a new math teacher I feel I dont grasp anything anymore :(

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
%282%2F3%29%5E-2%2A%284%2F5%29%5E-1
If you don't get negative exponents, just think of them
like this:
10^4 = 10000
10^3 = 1000
10^2 = 100
10^1 = 10
10^0 = 1
10^-1 = .1
10^-2 = .01
10^-3 = .001
10^-4 = .0001
In general, x%5E%28-a%29+=+1%2F%28x%5Ea%29
%282%2F3%29%5E-2%2A%284%2F5%29%5E-1
%281%2F%282%2F3%29%5E2%29%2A%281%2F%284%2F5%29%5E1%29
%281%2F%284%2F9%29%29%2A%281%2F%284%2F5%29%29
Now you just invert each fraction
%289%2F4%29%2A%285%2F4%29
45%2F16 answer