SOLUTION: a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $90 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $90 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the
Log On
Question 186415: a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $90 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the $20 coffee should be used? Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! a merchant has coffee worth $20 a pound that she wishes to mix with 80 pounds of coffee worth $90 a pound to get a mixture that can be sold for $60 a pound. how many pounds of the $20 coffee should be used?
-----------
Equation:
value + value = value
20x + 90*80 = 60(x+80)
20x = 90*80 = 60x + 60*80
-40x = -30*80
x = 30*2
x = 60 lbs (amt. of $20 coffee needed in the mixtue
------------------------------------------------------
Cheers,
Stan H.
You can put this solution on YOUR website! Let = pounds of $20 coffee used
given: = cost in dollars of $20 coffee used = cost in dollars of $90 coffee used = pounds of coffee in final mixture = cost in dollars of final mixture
-------------------
60 pounds of $20 coffee must be used
check:
OK
(