SOLUTION: If the first and third consecutive integers are added, the result is 63 less than five times the second integer. Find the third integer.

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Question 186401: If the first and third consecutive integers are added, the result is 63 less than five times the second integer. Find the third integer.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Let the three integers = x, x+1, x+2
:
If the first and third consecutive integers are added, the result is 63 less than five times the second integer.
x + (x+2) = 5(x+1) - 63
2x + 2 = 5x + 5 - 63
2x - 5x = 5 - 63 - 2
-3x = -60
x = %28-60%29%2F%28-3%29
x = +20 is the 1st integer
:
Find the third integer.
20 + 2 = 22 is the 3rd integer
:
:
Check solution:
first and third consecutive integers are added, the result is 63 less than
five times the second integer.
20 + 22 = 5(21) - 63
42 = 105 - 63
42 = 42