SOLUTION: The position of an object moving in a straight line is given by s=2tsquared-3t, where s is in meters and t is the time in seconds the object has been in motion. How long(to the nea
Question 186357: The position of an object moving in a straight line is given by s=2tsquared-3t, where s is in meters and t is the time in seconds the object has been in motion. How long(to the nearest tenth) will it take the object to move 6 meters? Answer by nerdybill(7384) (Show Source):
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s=2tsquared-3t
s=2t^2-3t
.
Set 's' to 6 and solve for 't':
s=2t^2-3t
6=2t^2-3t
0=2t^2-3t-6
Since we can't factor, we must use the quadratic equation.
Doing so yields:
t = {2.6, -1.1}
We can toss out the negative solution leaving
t = 2.6 seconds
.
Details of quadratic follows: