SOLUTION: The sum of two consecutive integers 111. Three times the larger integer less two times the smaller integer is 58. Find the value of the smaller integer

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Question 186175: The sum of two consecutive integers 111. Three times the larger integer less two times the smaller integer is 58. Find the value of the smaller integer
Answer by checkley77(12844) About Me  (Show Source):
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x+(x+1)=111 or 2x+1=111 or 2x=111-1 or 2x=110 or x=110/2 or x=55 is the smaller integer.
3(x+1)-2x=58
3(55+1)-2*55=58
3*56-110=58
168-110=58
58=58