SOLUTION: Compute the value of the discriminant and give the number of real solution to the quadractic equation 4x^2-x+5=0

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Compute the value of the discriminant and give the number of real solution to the quadractic equation 4x^2-x+5=0      Log On


   

Question 185733: Compute the value of the discriminant and give the number of real solution to the quadractic equation
4x^2-x+5=0
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2-x+5=0
x=%28-b%2B-sqrt%28b%5E2-4%2Aa%2Ac%29%29%2F%282%2Aa%29
x=(1+-sqrt[-1^2-4*4*5])/2*4
x=(1+-sqrt1-80)/8
x=(1+-sqrt-79)/8
x=(1-+8.888i)/8
x=(1+8.888i)/8
x=.125+-1.111i ans.