SOLUTION: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula
S = -16t^2 +v0t + S0. A rock
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-> SOLUTION: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula
S = -16t^2 +v0t + S0. A rock
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Question 185707: If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula
S = -16t^2 +v0t + S0. A rock is thrown into the air at 26 feet per second from a height of 13 feet. How long does it take to reach the earth?
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You can put this solution on YOUR website! If an object is given an initial velocity of v0 feet per second from a height of S0 feet, then its height S after t seconds is given by the formula
S = -16t^2 +v0t + S0. A rock is thrown into the air at 26 feet per second from a height of 13 feet. How long does it take to reach the earth?
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S(t) = -16t^2 +26t + 13
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When it reaches the earth its height is zero; solve for "t":
-16t^2 +26t + 13 = 0
t = [-26 +- sqrt(26^2 - 4*-16*13)/(-32)
t = [-26 +- sqrt(1508)]/(-32)
Positive solution:
t = [-26 - 38.83]/(-32)
t = 2.03 seconds
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Cheers,
Stan H.
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