SOLUTION: Which binomial is a factor of 6x^2 + x – 2?

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Question 185549: Which binomial is a factor of 6x^2 + x – 2?

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 6x%5E2%2Bx-2, we can see that the first coefficient is 6, the second coefficient is 1, and the last term is -2.


Now multiply the first coefficient 6 by the last term -2 to get %286%29%28-2%29=-12.


Now the question is: what two whole numbers multiply to -12 (the previous product) and add to the second coefficient 1?


To find these two numbers, we need to list all of the factors of -12 (the previous product).


Factors of -12:
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to -12.
1*(-12)
2*(-6)
3*(-4)
(-1)*(12)
(-2)*(6)
(-3)*(4)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient 1:


First NumberSecond NumberSum
1-121+(-12)=-11
2-62+(-6)=-4
3-43+(-4)=-1
-112-1+12=11
-26-2+6=4
-34-3+4=1



From the table, we can see that the two numbers -3 and 4 add to 1 (the middle coefficient).


So the two numbers -3 and 4 both multiply to -12 and add to 1


Now replace the middle term 1x with -3x%2B4x. Remember, -3 and 4 add to 1. So this shows us that -3x%2B4x=1x.


6x%5E2%2Bhighlight%28-3x%2B4x%29-2 Replace the second term 1x with -3x%2B4x.


%286x%5E2-3x%29%2B%284x-2%29 Group the terms into two pairs.


3x%282x-1%29%2B%284x-2%29 Factor out the GCF 3x from the first group.


3x%282x-1%29%2B2%282x-1%29 Factor out 2 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%283x%2B2%29%282x-1%29 Combine like terms. Or factor out the common term 2x-1

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Answer:


So 6x%5E2%2Bx-2 factors to %283x%2B2%29%282x-1%29.


This means that 3x%2B2 and 2x-1 are factors of 6x%5E2%2Bx-2