SOLUTION: Which binomial is factor of 2x^2 – 7x + 3?

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Question 185548: Which binomial is factor of 2x^2 – 7x + 3?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at the expression 2x%5E2-7x%2B3, we can see that the first coefficient is 2, the second coefficient is -7, and the last term is 3.


Now multiply the first coefficient 2 by the last term 3 to get %282%29%283%29=6.


Now the question is: what two whole numbers multiply to 6 (the previous product) and add to the second coefficient -7?


To find these two numbers, we need to list all of the factors of 6 (the previous product).


Factors of 6:
1,2,3,6
-1,-2,-3,-6


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 6.
1*6
2*3
(-1)*(-6)
(-2)*(-3)

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -7:


First NumberSecond NumberSum
161+6=7
232+3=5
-1-6-1+(-6)=-7
-2-3-2+(-3)=-5



From the table, we can see that the two numbers -1 and -6 add to -7 (the middle coefficient).


So the two numbers -1 and -6 both multiply to 6 and add to -7


Now replace the middle term -7x with -x-6x. Remember, -1 and -6 add to -7. So this shows us that -x-6x=-7x.


2x%5E2%2Bhighlight%28-x-6x%29%2B3 Replace the second term -7x with -x-6x.


%282x%5E2-x%29%2B%28-6x%2B3%29 Group the terms into two pairs.


x%282x-1%29%2B%28-6x%2B3%29 Factor out the GCF x from the first group.


x%282x-1%29-3%282x-1%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.


%28x-3%29%282x-1%29 Combine like terms. Or factor out the common term 2x-1

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Answer:


So 2x%5E2-7x%2B3 factors to %28x-3%29%282x-1%29.


So x-3 and 2x-1 are factors of 2x%5E2-7x%2B3