SOLUTION: Find two consecutive odd intergers such that twice the larger is 17 more than the smaller

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Question 185488This question is from textbook
: Find two consecutive odd intergers such that twice the larger is 17 more than the smaller This question is from textbook

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find two consecutive odd intergers such that twice the larger is 17 more than the smaller
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1st: 2x-1
2nd: 2x+1
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Equation:
2(2x+1)= (2x-1)+17
4x + 2 = 2x + 16
2x = 14
x = 7
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1st: 2x-1 = 13
2nd: 2n+1 = 15
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Cheers,
Stan H.