SOLUTION: Find the inverse of Y=(x-3)(x^2+3x+9)

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Question 185380This question is from textbook saxon algebra 2
: Find the inverse of Y=(x-3)(x^2+3x+9) This question is from textbook saxon algebra 2

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y=%28x-3%29%28x%5E2%2B3x%2B9%29 Start with the given equation.


y=x%28x%5E2%2B3x%2B9%29-3%28x%5E2%2B3x%2B9%29 Expand


y=x%5E3%2B3x%5E2%2B9x-3x%5E2-9x-27 Distribute


y=x%5E3-27 Combine like terms.


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x=y%5E3-27 Swap each x and y. The goal now is to solve for y


x%2B27=y%5E3 Add 27 to both sides.


root%283%2Cx%2B27%29=y Take the cube root of both sides to isolate y.


So the inverse is y=root%283%2Cx%2B27%29