SOLUTION: this is from a worksheet not a text book. I am grandma trying to help grandson The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Fin

Algebra ->  Systems-of-equations -> SOLUTION: this is from a worksheet not a text book. I am grandma trying to help grandson The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Fin      Log On


   



Question 185266: this is from a worksheet not a text book. I am grandma trying to help grandson
The perimeter of a rectangle is 160 ft. One fourth the length is the same as twice the width. Find the dimensions of the rectangle.
Thank you for your valued help!!

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter=160 = 2L+2W........eq 1
:
(1/4)L=2(W)........eq 2
:
rewrite eq 2 to L=4*2*W=8W....multiplied both sides by 4
:
now take L's value of 8W and plug that into eq 1
:
2(8W)+2W=160
:
18W=160
:
highlight%28W=8.89%29
:
L=8(8.89)=highlight%2871.12%29
:
2(71.12)+2(8.89)=142.2+17.78=159.98...rounding off caused us to be off a little