Question 185248: Bag contains marbles of 5 diff colors, 9 of each color. You select 4. How many diff ways can you choose 2 of one color, 1 of another color and 1 of yet another color?
I would have thought it was 9C2 x 9C1 x9C1 x 5C3 (5 colors, choose 3), but I know this isn't the answer. Can anyone assist?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Bag contains marbles of 5 diff colors, 9 of each color. You select 4. How many diff ways can you choose 2 of one color, 1 of another color and 1 of yet another color?
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Choose a color: 5 ways
Choose 2 marbles of that color: 9C2 ways
Choose another color: 4 ways:
Choose 1 marble of that color: 9 ways
Choose another color: 3 ways:
Choose 1 marble of that color: 9 ways
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Total # of choices:
5*4*3*9C2*9^2 = 174,960 ways
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Cheers,
Stan H.
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