SOLUTION: The sum of the squares of two consecutive intergers is 25.

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Question 185158: The sum of the squares of two consecutive intergers is 25.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
let x be one number, then (x+1) is the other number
x%5E2+%2B+%28x%2B1%29%5E2+=+25
x%5E2+%2B+x%5E2+%2B+2x+%2B+1+=+25
2x%5E2+%2B+2x+-24+=+0
x%5E2+%2B+x+-12+=+0
%28x%2B4%29%28x-3%29+=+0
x = -4 and x = 3
so then numbers are 3,4 and -4,-3