SOLUTION: THE ATTENDANCE AT A SCHOOL CONCERT WAS 578. ADMISSION COST $2.00 FOR ADULTS AND $1.50 FOR CHILDREN. THE RECEIPTS WERE $985.00. HOW MANY ADULTS AND HOW MANY CHILDREN ATTENDED THE

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: THE ATTENDANCE AT A SCHOOL CONCERT WAS 578. ADMISSION COST $2.00 FOR ADULTS AND $1.50 FOR CHILDREN. THE RECEIPTS WERE $985.00. HOW MANY ADULTS AND HOW MANY CHILDREN ATTENDED THE      Log On


   

Question 185146: THE ATTENDANCE AT A SCHOOL CONCERT WAS 578.
ADMISSION COST $2.00 FOR ADULTS AND $1.50 FOR CHILDREN.
THE RECEIPTS WERE $985.00.
HOW MANY ADULTS AND HOW MANY CHILDREN ATTENDED THE CONCERT?
Answer by jigs_ipan(5) About Me  (Show Source):
You can put this solution on YOUR website!
solution:
let x be the number of adult attented
let y be the number of children attended
given:
cost of adult = $2.00
cost of child = $1.50
x + y = 578 (equation 1)
2.00x + 1.50y = 985 (equation 2)
x + y = 578 => x = 578 - y (equation 3)
2.00(578 - y) + 1.50y = 985 (substituting the value of x in eq. 1 to eq. 2)
1156 - 2.00y + 1.50y = 985
-2.00y + 1.50y = 985 - 1156
-0.50y = -171 (diving both sides by -0.50)
y = 342
x = 578 - y (eq. 3)
x = 578 - (342) (substituting the value of y which is 342))
x = 236
therefore, the number of adults attended the concert was 236 and the number of children attended was 342...