SOLUTION: SUSAN WANTS TO HAVE BUSINESS CARDS PRINTED. ONE STYLE WILL COST $25 PLUS 2CENTS PER CARD. ANOTHER STYLE WILL COST $10 PLUS 5CENTS FOR EVERY CARD. FOR HOW MANY CARDS WILL THE COST

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: SUSAN WANTS TO HAVE BUSINESS CARDS PRINTED. ONE STYLE WILL COST $25 PLUS 2CENTS PER CARD. ANOTHER STYLE WILL COST $10 PLUS 5CENTS FOR EVERY CARD. FOR HOW MANY CARDS WILL THE COST       Log On


   



Question 185134: SUSAN WANTS TO HAVE BUSINESS CARDS PRINTED. ONE STYLE WILL COST $25 PLUS 2CENTS PER CARD. ANOTHER STYLE WILL COST $10 PLUS 5CENTS FOR EVERY CARD.
FOR HOW MANY CARDS WILL THE COST BE THE SAME FOR BOTH STYLES?

Answer by swiemers(10) About Me  (Show Source):
You can put this solution on YOUR website!
To do this, you need to make them equal each other in an equation. Therefore, we could say:
25 + .02x = 10 + .05x
where x = the number of cards to be printed. They want to know when they are the same, so you set them equal to each other. Then you need to solve for x.
25 + .02x = 10 + .05x
First combine the x variables by subtracting the .02x and moving it over to the .05x and you get:
25 = 10 + .03x
Then you want to isolate the x variable so we have to move the 10 over. We do so by subtracting it from both sides and we get:
15 = .03x
Then you divide each side by .03 to get x by itself and you get:
x = 500
Therefore, the cost will be the same at 500 cards.
Hope this helps! Good luck! Sandy :-)