SOLUTION: Candy sells for $1.30 per lb is to be mixed with candy selling for $0.90 per lb to get 100 lb of a mix that will sell for $1 per lb. How much of each type should be used?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Candy sells for $1.30 per lb is to be mixed with candy selling for $0.90 per lb to get 100 lb of a mix that will sell for $1 per lb. How much of each type should be used?
Log On
Question 185116: Candy sells for $1.30 per lb is to be mixed with candy selling for $0.90 per lb to get 100 lb of a mix that will sell for $1 per lb. How much of each type should be used? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! Let x be the number of lbs selling for 1.30. 100-x lbs selling for .90
100 lbs selling for $1/lb costs $100.
.
1.3x+.9(100-x)=100
1.3x+90-.9x=100
0.4x=10
x=25 lbs
75 lbs selling for .90
.
Ed
