SOLUTION: Use slope intercept to graph the equation. I don't know what my points should be! y=8/7x-1

Algebra ->  Graphs -> SOLUTION: Use slope intercept to graph the equation. I don't know what my points should be! y=8/7x-1      Log On


   

Question 184869: Use slope intercept to graph the equation. I don't know what my points should be!
y=8/7x-1
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Your equation is already in the "slope-intercept" form of y = mx+b
y+=+%288%2F7%29x-1 where the slope, m+=+8%2F7 and the y-intercept is b+=+-1
Now this is a linear equation, which means it will graph into a straight line, and you need only two points to define a straight line.
To get those two points, you first set x = 0 and solve the equation for y, then you set y = 0 and solve the equation for x, like this...
y+=+%288%2F7%29x-1 Set x = 0 and solve for y.
y+=+%288%2F7%29%280%29-1
y+=+-1 So the first point is (0, -1)
y+=+%288%2F7%29x-1 Set y = 0 and solve for x.
0+=+%288%2F7%29x-1 Add 1 to both sides.
1+=+%288%2F7%29x Now multiply both sides by the multiplicative inverse of 8%2F7 and this is 7%2F8
1%287%2F8%29+=+x The second point is (7/8, 0)
Now plot these two points on your coordinate graph paper and joint the point with a straight.
graph%28400%2C400%2C-5%2C5%2C-5%2C5%2C%288%2F7%29x-1%29