SOLUTION: Could someone please help me solve this? Thank you. If Punxsutawney Phil sees his shadow on the first Monday in February, then legend says that winter will last 6 more weeks. In

Algebra ->  Probability-and-statistics -> SOLUTION: Could someone please help me solve this? Thank you. If Punxsutawney Phil sees his shadow on the first Monday in February, then legend says that winter will last 6 more weeks. In      Log On


   

Question 184596: Could someone please help me solve this? Thank you.
If Punxsutawney Phil sees his shadow on the first Monday in February, then legend says that winter will last 6 more weeks. In 118 years, Phil has seen his shadow 104 times. (a) What is the probability that Phil will see his shadow on a randomly chosen Groundhog Day? (b) What kind of probability is this?


Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a)

P(see his shadow) = (number of times he's seen his shadow)/(number of times total)

P(see his shadow) = 104/118

P(see his shadow) = 52/59

P(see his shadow) = 0.881


Multiply by 100 to get 88.1%

So the chance he'll see his shadow is 88.1%


b)

This is known as empirical probability