SOLUTION: If one side of a square is increased by 8 cm and an adjacent side decreased by 2 cm, a rectangle is formed whose perimeter is 40 cm. Find the length of a side of the square

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Question 184561This question is from textbook Algebra and trigonometry structure and method
: If one side of a square is increased by 8 cm and an adjacent side decreased by 2 cm, a rectangle is formed whose perimeter is 40 cm. Find the length of a side of the square This question is from textbook Algebra and trigonometry structure and method

Answer by J2R2R(94) About Me  (Show Source):
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Let x be the side of the square.

The new rectangle has sides x + 8 (twice) and x – 2 (twice).

Therefore the perimeter = 2(x + 8) + 2(x – 2) = 4x + 12.

Now 4x + 12 = 40; therefore 4x = 28; x = 7.

The length of a side of the square is 7 cm.