Question 184558: I'm not sure about this.
Graph the linear equation by finding and plotting its intercepts.
y=-5x
Thanks
Found 3 solutions by solver91311, checkley77, vleith:
Answer by solver91311(24713)   (Show Source):
You can put this solution on YOUR website!
The process for finding the intercepts requires substituting 0 for each of the variables and then determining the value of the other variable to give you two points: (a,0) which is the x-intercept (the point where the graph intersects the x-axis and (0,b) which is the y-intercept. This would give you two points that will define the line that is the graph of your equation.
For this equation:
 = 0)
and
The problem you have with the given equation is that the x- and y-intercepts are the same point, namely the origin (0,0), and one point is insufficient to define a line. Consequently, just finding the intercepts is not enough to create the graph of this equation.
To find a second point on the line, you need to find a point that is not an intercept. Select a value for x other than 0, substitute that value, and determine the resulting value for y. The selected value and the resulting value can be formed into an ordered pair that you can graph to establish your second point. (I chose 1 as a value for x, but you could choose anything you like so long as it is not 0)
 = -5)
Now you have two points, (0,0) and (1,-5). Plot them then draw a line through them to give you your graph.
John
Answer by checkley77(12844)  (Show Source):
You can put this solution on YOUR website! y=-5x
To find the x intercept set y=0
0=-5x
x=0 (0,0)
To find the y intercept set x=o
y=-5*0
y=0 (0,0)
The slope=-5
Thus when y=5 x=-1 or when y=-5 x=1
 (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = -5x).
Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Intercepts are points that are on the axis. So one or the other coordinate of the point must be 0.
So
(0,y) and (x,0). Solve for them as follows.
Assume x =0, using y=-5x
y = -5*0 = 0
So the x intercept is (0,0)
Assume y=0. Using y = -5x
0 = -5x
0 = x
So the y intercept is (0,0)
What you have are 'two points that are the same point'. So you cannot plot the line using just the intercepts, since this line passes thru the origin.
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