SOLUTION: A line that passes through (7,3) and has a slope of -1.
What I've done so far y= 2/3(-1)-4
y=2/3(3/2)=6/6= 1 - 4 = -3
(7,3) and (1,-3)
Algebra ->
Linear-equations
-> SOLUTION: A line that passes through (7,3) and has a slope of -1.
What I've done so far y= 2/3(-1)-4
y=2/3(3/2)=6/6= 1 - 4 = -3
(7,3) and (1,-3)
Log On
Question 184523: A line that passes through (7,3) and has a slope of -1.
What I've done so far y= 2/3(-1)-4
y=2/3(3/2)=6/6= 1 - 4 = -3
(7,3) and (1,-3) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A line that passes through (7,3) and has a slope of -1.
What I've done so far y= 2/3(-1)-4
y=2/3(3/2)=6/6= 1 - 4 = -3
----------------------
Use
y-y1 = m*(x-x1) where (x1,y1) is the point (7,3) and m is the slope.
y-3 = -1(x-7)
y-3 = -x+7
x+y = 10
