SOLUTION: I need someone's help on this {{{ ((2*x*y^2*z^4)/(3*x*y*z^-1))^-2 }}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need someone's help on this {{{ ((2*x*y^2*z^4)/(3*x*y*z^-1))^-2 }}}      Log On


   

Question 18447: I need someone's help on this +%28%282%2Ax%2Ay%5E2%2Az%5E4%29%2F%283%2Ax%2Ay%2Az%5E-1%29%29%5E-2++
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
+%28%282%2Ax%2Ay%5E2%2Az%5E4%29%2F%283%2Ax%2Ay%2Az%5E-1%29%29%5E-2++
x cancels off from the numerator and denominator
+%28%282%2Ay%5E2%2Az%5E4%29%2F%283%2Ay%2Az%5E-1%29%29%5E-2++
Raise everything to the power (-2)

+%28%282%5E-2%2Ay%5E-4%2Az%5E-8%29%2F%283%5E-2%2Ay%5E-2%2Az%5E2%29%29++
Negative Powers can reciprocate the variable
ie x^-2 becomes 1/x^2
+%28%283%5E2%2Ay%5E2%29%2F%282%5E2%2Ay%5E4%2Az%5E%282%2B8%29%29%29++
+%289%2Ay%5E2%29%2F%28+4%2Ay%5E4%2Az%5E%282%2B8%29+%29++
+%289%2Ay%5E2%29%2F%28+4%2Ay%5E4%2Az%5E10+%29++
+9%2F%28+4%2Ay%5E%284-2%29%2Az%5E10+%29++
+9%2F%28+4%2Ay%5E2%2Az%5E10+%29++


Hope this helps,
Prabhat