SOLUTION: A school district is combining 2 schools that will have a total of 1000 students, 42% of whom are african american. 90% of one school is african american and 10% of the other is af
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Question 184467: A school district is combining 2 schools that will have a total of 1000 students, 42% of whom are african american. 90% of one school is african american and 10% of the other is african american. How may students are in each school.
I've tried solving it several different ways x/2 + 420 = 1000 and x + y - 420 = 1000 for example and just can't figure this out! Please help - thank you very much! Answer by solver91311(24713) (Show Source):
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If 42% of the new school is african-american, then out of the 1000 students at the new school, 420 are african-american.
If x represents the number of students at one school and y represents the number of students at the second school. We can establish three things:
1. The sum of the students from the 2 schools must equal 1000:
(1)
2. 90% of the first school is african-american, so you can say the number of african american students at school 1 is:
3. Likewise, the number of african american students at the second school is:
And we know that 420 is the sum of the african-americans at both schools, so:
(2)
Now (1) and (2) form a system of linear equations that can be solved by either substitution or elimination.