SOLUTION: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? I came up with 75.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food? I came up with 75.       Log On


   

Question 184429: If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?
I came up with 75.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
If four out of five doctors prefer fast food, then at a convention of 445 doctors, how many prefer fast food?
I came up with 75.
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4:5 is the same as 4x:5x where 4x is the number that prefer fast food.
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4x + 5x = 445
9x = 445
x = 49.44444
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Then 4x = 197.78
Rounding donw: 197 or the 445 preferred fast food.
Cheers,
Stan H.