SOLUTION: Solve for x log (base of 2)(x^2+8) = log (base of 2)x + log(base of 2) 6

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Question 184394: Solve for x
log (base of 2)(x^2+8) = log (base of 2)x + log(base of 2) 6
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
log[2](x^2+8) = log[2]x + log[2]6
2^log[2](x^2+8) = 2^log[2]x * 2^log[2]6
x^2+8=6x
x^2-6x+8=0
(x-4)(x-2)=0
x=4, x=2
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Ed