SOLUTION:
DONT DO THIS ONE 107. Wind chill. The wind chill temperature W (how cold the air feels) is determined by the air temperature t and the wind velocity v. Through experimentation in
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DONT DO THIS ONE 107. Wind chill. The wind chill temperature W (how cold the air feels) is determined by the air temperature t and the wind velocity v. Through experimentation in
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Question 184385:
DONT DO THIS ONE 107. Wind chill. The wind chill temperature W (how cold the air feels) is determined by the air temperature t and the wind velocity v. Through experimentation in Antarctica, Paul Siple developed a formula for W: W: W=91.4-(10.5+6.7Sqrt(x)v-0.45v)(457-5t)/110 , where W and t are in degrees Fahrenheit and v is in miles per hour (mph).
a) Find W to the nearest whole degree when t =25°F and v=20 mph.
b) Use the accompanying graph to estimate W when t = 25°F and v = 30 mph.
108. Comparing wind chills. Use the formula from Exercise 107 to determine who will feel colder: a person in Minneapolis at 10°F with a 15-mph wind or a person in Chicago at 20°F with a 25-mph wind.
You can put this solution on YOUR website! 108. Comparing wind chills. Use the formula from Exercise 107 to determine who will feel colder: a person in Minneapolis at 10°F with a 15-mph wind or a person in Chicago at 20°F with a 25-mph wind.
:
I think the formula should be:
W = 91.4-
:
Minneapolis: t=10, v=15
W = 91.4-
:
W = 91.4-
:
W = 91.4-
:
W = 91.4-
:
W = 91.4-
:
W = 91.4 - 109.89
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W = -18.5 degrees wind chill
:
:
Chicago: t=20, v=25
W = 91.4-
:
W = 91.4-
:
W = 91.4-
:
W = 91.4-
:
W = 91.4-
:
W = 91.4 - 106.29
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W = -14.88 degrees wind chill
:
It's a little colder in Minneapolis, but I doubt if one could notice it