SOLUTION: Three times the smallest of three consecutive even integers is two more than twice the largest. Find the integers. This what I tried. 3x=2[x+2+2(x+4)] 3x=2[x+2+2x+8] 3x=2[

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Three times the smallest of three consecutive even integers is two more than twice the largest. Find the integers. This what I tried. 3x=2[x+2+2(x+4)] 3x=2[x+2+2x+8] 3x=2[      Log On


   

Question 184353: Three times the smallest of three consecutive even integers is two more than twice the largest. Find the integers.
This what I tried.
3x=2[x+2+2(x+4)]
3x=2[x+2+2x+8]
3x=2[3x+10]
3x=6x+20
-6x=-6x
3x-6x=20
-3x=20
x=20/-3
x=?
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
"Three times the smallest of three consecutive even integers is two more than twice the largest" ----> 3(2x)=2(2x+4)+2


3(2x)=2(2x+4)+2

6x=2(2x+4)+2


6x=4x+8+2

6x-4x=8+2

2x=10

x=5

Nums: 2*5, 2*5+2, 2*5+4 ---> 10, 12, 14

Ans: numbers are 10, 12, 14