SOLUTION: A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far d
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-> SOLUTION: A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far d
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: A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog? This question is from textbook
You can put this solution on YOUR website! A student walks and jogs to college each day. She averages 5 km/h walking and 9km/h jogging. The distance from home to college is 8 km, and she makes the trip in 1 hr. How far does the student jog?
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Walking DATA:
distance = x km ; rate = 5 km/h ; time = d/r = x/5 hr
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Jogging DATA:
distance = (8-x) km ; rate = 9 km/h ; time = (8-x)/9 hr
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Equation
time + time = 1 hr
x/5 + (8-x)/9 = 1
Multiply thru by 45 to get:
9x + 5(8-x) = 45
9x + 40 - 5x = 45
4x = 5
x = 5/4 km (walking distance
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8-x = 8 -5/4 = 27/4 km (jogging distance)
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Cheers
Stan H.
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