SOLUTION: Betty and Sue use a metal that is 17.3% copper to make jewelry. How many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy?
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Betty and Sue use a metal that is 17.3% copper to make jewelry. How many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy?
Log On
Question 184214This question is from textbook
: Betty and Sue use a metal that is 17.3% copper to make jewelry. How many ounces of a 17% alloy must be mixed with a 18% alloy to form 80 ounces of the desired alloy? This question is from textbook
You can put this solution on YOUR website! Betty and Sue use a metal that is 17.3% copper to make jewelry.
How many ounces of a 17% alloy must be mixed with a 18% alloy
to form 80 ounces of the desired alloy?
:
Let x = amt of 18% alloy required
:
It states the total of the two alloys will be 80 oz, therefore:
(80-x) = amt of 17% alloy required
:
Write the decimal equiv equation:
:
.17(80-x) + .18x = .173(80)
:
13.6 - .17x + .18x = 13.84
:
-.17x + .18x = 13.84 - 13.6
:
.01x = .24
x =
x = 24 oz of 18% copper
and
80 - 24 = 56 oz of 17% copper
:
:
Check solution in original equation
.17(56) + .18(24) = .173(80)
9.52 + 4.32 = 13.84; confirms our solutions
