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| Question 184173:  #3
 what does this look like in a graph after being plotted out?
 First, set Y to 0 then solve for X
 2X - 7
 2X = -7
 X = -7/2
 Now plot (-7/2, 0)
 Then set X to 0 and solve for Y
 Y = -2(0) - 7
 Y = -7
 Now plot (0,-7)
 1 = -2x -7
 8 = -2x
 8/-2 = x
 x = -4
 Plot (-4, 1)
 I figured out this much, but cannot figure out how to get the graph. the original problem was to graph: 7.1x - 3.9y = 1.4
 Help is appreciated. This is going on for quite a while and I really want to find the way to do this.
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! what does this look like in a graph after being plotted out? First, set Y to 0 then solve for X
 2X - 7
 2X = -7
 X = -7/2
 Now plot (-7/2, 0)
 Then set X to 0 and solve for Y
 Y = -2(0) - 7
 Y = -7
 Now plot (0,-7)
 1 = -2x -7
 8 = -2x
 8/-2 = x
 x = -4
 Plot (-4, 1)
 I figured out this much, but cannot figure out how to get the graph. the original problem was to graph: 7.1x - 3.9y = 1.4
 Help is appreciated. This is going on for quite a while and I really want to find the way to do this.
 ----------------------
 It's a straight line, so only 2 points are needed to graph it.
 7.1x - 3.9y = 1.4
 Set x = 0, solve for y, as you said, but I don't know where you get your numbers.
 at x = 0: 7.1*0 - 3.9y = 1.4
 y = -14/39 --> (0,-14/39)
 ------------
 at y = 0: 7.1x = 1.4
 x = 14/71 --> (14/71,0)
 The 2 points are (apx) (0,-0.359) and (0.197,0)
 
 
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