SOLUTION: write the equation of the line that passes through (7,3) and (2,5) in slope intercept form.

Algebra ->  Linear-equations -> SOLUTION: write the equation of the line that passes through (7,3) and (2,5) in slope intercept form.      Log On


   

Question 183633: write the equation of the line that passes through (7,3) and (2,5) in slope intercept form.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


Note: is the first point and is the second point .


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%285-3%29%2F%282-7%29 Plug in y%5B2%5D=5, y%5B1%5D=3, x%5B2%5D=2, and x%5B1%5D=7


m=%282%29%2F%282-7%29 Subtract 3 from 5 to get 2


m=%282%29%2F%28-5%29 Subtract 7 from 2 to get -5


m=-2%2F5 Reduce


So the slope of the line that goes through the points and is m=-2%2F5


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-3=%28-2%2F5%29%28x-7%29 Plug in m=-2%2F5, x%5B1%5D=7, and y%5B1%5D=3


y-3=%28-2%2F5%29x%2B%28-2%2F5%29%28-7%29 Distribute


y-3=%28-2%2F5%29x%2B14%2F5 Multiply


y=%28-2%2F5%29x%2B14%2F5%2B3 Add 3 to both sides.


y=%28-2%2F5%29x%2B29%2F5 Combine like terms.


So the equation that goes through the points and is y=%28-2%2F5%29x%2B29%2F5