SOLUTION: Factor completely. {{{20x^3y^2+8x^9y^3-16x^5y^2}}}
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Question 183573
:
Factor completely.
Found 2 solutions by
stanbon, checkley77
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Answer by
stanbon(75887)
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Factor completely.
20x^3y^2+8x^9y^3-16x^5y^2
Look for a common factor:
4x^3y^2 [5 + 2x^6y - 4x^2]
================================
Cheers,
Stan H.
Answer by
checkley77(12844)
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4X^3Y^2(5+2X^6Y-4X^2) ans.