SOLUTION: In 15 years, Maya will be twice as old as David is now. In 15 years, David will be as old as Maya will be in 10 years from now. How old are they now?

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Question 183442: In 15 years, Maya will be twice as old as David is now. In 15 years, David will be as old as Maya will be in 10 years from now. How old are they now?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let m= Maya's age now
Let d= David's age now
In 15 years, Maya's age = m+%2B+15
In 15 years, David'd age = d+%2B+15
In 10 years, Maya's age = m+%2B+10
given:
(1) m+%2B+15+=+2d
(2) d+%2B+15+=+m+%2B+10
This is 2 equations and 2 unknowns, so it's solvable
(1) m+%2B+15+=+2d
(2) m+%2B+10+=+d+%2B+15
-------------------------
(1) m+-+2d+%2B+15+=+0
(2) m+-+d+-+5+=+0
-------------------------
Subtract (2) from (1)
-------------------------
(1) m+-+2d+%2B+15+=+0
(2) -m+%2B+d+%2B+5+=+0
(3) -d+%2B+20+=+0
(3) d+=+20
Plug this result back into (2)
(2) d+%2B+15+=+m+%2B+10
(2) 20+%2B+15+=+m+%2B+10
(2) 35+=+m+%2B+10
(2) m+=+25
Maya's age now is 25 and David's age now is 20
check:
given:
(1) m+%2B+15+=+2d
(1) 25+%2B+15+=+2%2A20
(1) 40+=+40
-----------------
(2) d+%2B+15+=+m+%2B+10
(2) 20+%2B+15+=+25+%2B+10
(2) 35+=+35
OK