Question 183380: I understand the examples you have given to find the sum of sequences but i have a problem which i couldn't find an example that will help me.
The Question:
In an arithmetic series, the terms of the series are equally spread out. For example, in
1 + 5 + 9 + 13 + 17, consecutive terms are 4 apart. If the first term in an arithmetic series is
3, the last term is 136, and the sum is 1,390, what are the first 3 terms?
I would like for you to show me a formula that will help me with this question because i have many problems on my homework that is this way.
Thank you
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The Question:
In an arithmetic series, the terms of the series are equally spread out. For example, in
1 + 5 + 9 + 13 + 17, consecutive terms are 4 apart. If the first term in an arithmetic series is
3, the last term is 136, and the sum is 1,390, what are the first 3 terms?
I would like for you to show me a formula that will help me with this question because i have many problems on my homework that is this way.
------------------------------------
The nth term: a(n) = a(1) + (n-1)d where d is the difference between
two consecutive terms.
The sum of n terms: S(n) = (n/2)[a(1) + a(n)]
---------------------------------------------------
You could Google "arithmetic series" and find out more about their properties.
Cheers,
Stan H.
|
|
|