SOLUTION: find three consecutive even integers if the sum of the first two minus the third is 16

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Question 183303: find three consecutive even integers if the sum of the first two minus the third is 16
Answer by jim_thompson5910(35256) About Me  (Show Source):
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Consecutive even integers follow the pattern: 2x, 2x+2, 2x+4, etc...


So "the sum of the first two minus the third is 16", translates to the equation %282x%29%2B%282x%2B2%29-%282x%2B4%29=16


%282x%29%2B%282x%2B2%29-%282x%2B4%29=16


2x%2B2x%2B2-2x-4=16 Distribute.


2x-2=16 Combine like terms on the left side.


2x=16%2B2 Add 2 to both sides.


2x=18 Combine like terms on the right side.


x=%2818%29%2F%282%29 Divide both sides by 2 to isolate x.


x=9 Reduce.


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Answer:

So the answer is x=9


This means that the three numbers are

2%289%29=18

2%289%29%2B2=18%2B2=20

2%289%29%2B4=18%2B4=22


In short, the numbers are 18, 20, and 22