SOLUTION: {{{ sqrt( 4-7x ) }}} = {{{ sqrt( 2x ) }}}
Hi,
I have been squaring both sides to get rid of the radical signs: 4-7x = 2x. x = 4/9 is what I'm coming up with, but the answer ke
Algebra ->
Radicals
-> SOLUTION: {{{ sqrt( 4-7x ) }}} = {{{ sqrt( 2x ) }}}
Hi,
I have been squaring both sides to get rid of the radical signs: 4-7x = 2x. x = 4/9 is what I'm coming up with, but the answer ke
Log On
Question 183287This question is from textbook Precalculus
: =
Hi,
I have been squaring both sides to get rid of the radical signs: 4-7x = 2x. x = 4/9 is what I'm coming up with, but the answer key says x = 1/2. I'm missing something. Any help explaining this problem would be greatly appreciated.
Thanking you in advance,
Lynn Scott
This question is from textbook Precalculus