SOLUTION: 2. grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. how long will it take will to catch up to grace?

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Question 183276: 2. grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. how long will it take will to catch up to grace?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
grace starts jogging home at 5 km/hr. will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. how long will it take will to catch up to grace?
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In 10 minutes, Grace is 5/6 km away.
Will is traveling 10 km/hr wrt (with respect to) Grace.
They will converge in (5/6)/10 hours = 5/60 hours
= 5 minutes.
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PS stanbon got it right until he said 1/12 hour is 6 minutes.
1/12 hour = 5 minutes.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
Grace starts jogging home at 5 km/hr. Will leaves 10 minutes later on a bike (from the same place) riding at 15 km/hr. How long will it take Will to catch up to Grace?
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Grace DATA:
rate = 5 km/h ; time = x hrs ; distance = rt = 5x km
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Will DATA:
rate = 15 km/h ; time = (x-(1/6)) hrs ; distance = rt = 15(x-(1/6)) km
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Equation:
distance = distance
5x = 15(x - (1/6))
5x = 15x - (5/2)
10x = (5/2)
x = 1/4 hr
x - (1/6) = (1/4)-(1/6) = (6-4)/24 = 2/24 = 1/12 hr. or 6 minutes
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Cheers,
Stan H.