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Question 183115: 1 .Write the standard form of the equation of the line passing thru each pair of points
(-1,-7) and (1,3)
(5, 3) and (-4,3)
2. Give an equation in slope intercept form of the line satisfying the given conditions:
has y intercept 5 and slope -3/4
has slope -3 and passes through (2, -4)
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! 1 .Write the standard form of the equation of the line passing thru each pair of points
(-1,-7) and (1,3)
(5, 3) and (-4,3)
There are 2 ways to do these. I'll use the long way on the 1st one.
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1st, find the slope, m, of the line thru the points.
m = (diffy)/(diffx)
m = (3-(-7))/(1-(-1))
m = 5
Then use either point:
y-y1 = m*(x-x1)
y-3 = 5(x-1)
y-3 = 5x-5
5x-y = 2
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The simpler method:
|+x y 1|
|+5 3 1| = 0
|-4 3 1|
(The plus signs are for alignment only.)
x(3-3) - y(5+4) + (15+12) = 0
-9y = -27
y = 3
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2. Give an equation in slope intercept form of the line satisfying the given conditions:
has y intercept 5 and slope -3/4
y = mx+ b where m=slope and b = y-intercept
y = (-3/4)x + 5
That's all, it was given.
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has slope -3 and passes through (2, -4)
y-y1 = m(x-x1)
y+4 = -3(x-2)
y+4 = -3x+6
y = -3x+2
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