SOLUTION: 1.moonshine has 50 liters of a 70% alcohol solution.how many liters of pure alcohol must be added to obtain an 80% alcohol solution 2.how many kg of pure salt must be added to 20

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Question 183089: 1.moonshine has 50 liters of a 70% alcohol solution.how many liters of pure alcohol must be added to obtain an 80% alcohol solution
2.how many kg of pure salt must be added to 20 kg of a 10% salt solution to obtain a 25% salt solution
3. how much pure acid must be added to 6 ml of a 5% acid solution to produce a 40% acid solution?
Answer by stanbon(75887) About Me  (Show Source):
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1.moonshine has 50 liters of a 70% alcohol solution. How many liters of pure alcohol must be added to obtain an 80% alcohol solution?
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Equation:
active + active = active
0.70*50 + 1.00x = 0.80(50+x)
solve for "x"
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2.how many kg of pure salt must be added to 20 kg of a 10% salt solution to obtain a 25% salt solution
---
Equation:
active + active = active
0.10*20 + 1.00x = 0.25(20+x)
solve for "x"
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3. how much pure acid must be added to 6 ml of a 5% acid solution to produce a 40% acid solution?
---
Equation:
active + active = active
0.05*6 + 1.00x = 0.40(6+x)
solve for "x"
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Cheers,
Stan H.