SOLUTION: A mass of iodine-131 atoms decays in such a way that half decay every 8 days. What portion of the original mass remains after 32 days?

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Question 183019This question is from textbook saxon algebra 2
: A mass of iodine-131 atoms decays in such a way that half decay every 8 days. What portion of the original mass remains after 32 days? This question is from textbook saxon algebra 2

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
4 = 32/8
So 1%2F2+%2A+1%2F2+%2A+1%2F2+%2A+1%2F2+=+1%2F16+=+1%2F%282%5E4%29
1/16 of the orginal amount is left 32 days