SOLUTION: The perimeter of a rectangle is 112 inches. The length exceeds the width by 8 inches. Find the length and the width.
The length is ________ inches.
(type an intreger or decimal
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-> SOLUTION: The perimeter of a rectangle is 112 inches. The length exceeds the width by 8 inches. Find the length and the width.
The length is ________ inches.
(type an intreger or decimal
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Question 182952: The perimeter of a rectangle is 112 inches. The length exceeds the width by 8 inches. Find the length and the width.
The length is ________ inches.
(type an intreger or decimal.)
The width is ________ inches.
(type an intreger or decimal) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 112 inches. The length exceeds the width by 8 inches. Find the length and the width.
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Perimeter = 2(L + W)
112 = 2((x+8) + x)
56 = 2x + 8
2x = 48
x = 24 in (width of the rectangle)
x+8 = 32 in (length of the rectangle)
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Cheers,
Stan H.
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