SOLUTION: Please solve this equation: {{{2^(2x)-32^x-18=0}}}

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Question 182853: Please solve this equation: 2%5E%282x%29-32%5Ex-18=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%282x%29-%282%5E5%29%5Ex-18=0
2%5E%282x%29-2%5E%285x%29-18=0
2%5E%282x%29-2%5E%285x%29=18
Here's a graph of both 2%5E%282x%29(in red) and 2%5E%285x%29(in green).
+graph%28+300%2C+300%2C+-5%2C+2%2C+-2%2C+4%2C+2%5E%282x%29%2C+2%5E%285x%29%29+
The only time that 2%5E%282x%29 is greater than 2%5E%285x%29 is when x<0.
At that point, both values are less than one and their difference cannot equal 18.
When x>0, 2%5E%285x%29 is always greater than 2%5E%282x%29, the difference cannot be 18.
There is no solution.