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Question 182670: Please help, thank you very much. Also please try to guide me along with your answer, thank you!
The tens digit of a two-digit number is 6 more than the ones digit. The sum of the number, and the number formed by reversing the digits is 88. Find the number.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The tens digit of a two-digit number is 6 more than the ones digit. The sum of the number, and the number formed by reversing the digits is 88. Find the number.
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Let the number be 10t+u. "t" is the tens digit; "u" is the units digit.
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Equations:
t = u + 6
10t+u + 10u+t = 88
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Rearrange:
t = u + 6
11t + 11u = 88
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Simplify
t - u = 6
t + u = 8
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Add to solve for "t":
2t = 14
t = 7 (the tens digit)
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Since t+u = 8, u = 1
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The number is 8*10+1 = 81
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Cheers,
Stan H.
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