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Question 182601: Due to the curvature of the earth, the maximum distance D that you can see from the top of a tall building or from an airplane at height h is given by the function below where r = 3960 mi is the radius of the earth and D and h are measured in miles.
D(h)= square root (2rh+h^2)
(a) Find D(0.4) and D(0.6).
D(0.4) = i figured out this one...56.3
D(0.6) = i figured out this one...68.9
(b) How far can you see from the observation deck of Toronto's CN Tower, 1135 ft above the ground?...i cant figure this out cuz u have to change it to miles instead of feet
_______miles
(c) Suppose that a commercial aircraft is flying at an altitude of 4.4 mi. How far can the pilot see?
_______miles...i figured this one out too...186.7
I just need help on the 3rd problem thanks!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Due to the curvature of the earth, the maximum distance D that you can see from the top of a tall building or from an airplane at height h is given by the function below where r = 3960 mi is the radius of the earth and D and h are measured in miles.
D(h)= square root (2rh+h^2)
(a) Find D(0.4) and D(0.6).
D(0.4) = i figured out this one...56.3
D(0.6) = i figured out this one...68.9
(b) How far can you see from the observation deck of Toronto's CN Tower, 1135 ft above the ground?...i cant figure this out cuz u have to change it to miles instead of feet
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(1135 ft)(1 mi/5280) = 0.215 miles
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D(0.215) = sqrt(2*3960*0.215 + 0.215^2) = 41.266 miles
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(c) Suppose that a commercial aircraft is flying at an altitude of 4.4 mi. How far can the pilot see?
_______miles...i figured this one out too...186.7
I just need help on the 3rd problem thanks!!
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Cheers,
San H.
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